HEXCO · Polytechnic · NC Accountancy

Financial Mathematics and Statistics 1: Business Computations

Learning Outcome 1 of 3

Free HEXCO NC Accountancy notes on Business Computations, learning outcome 1 of 3 in Financial Mathematics and Statistics 1. Business computations, financial statistics and the time value of money. Semester 2, module 310/22/M05.

Here we learn how to solve business problems with linear equations, work with ratios, rates, percentages, mixtures and proportions, calculate discounts and commissions, compare hire purchase with cash prices, and convert currencies.

Pricing goods, sharing profits, paying commission and buying on credit all depend on a few basic calculations, so mastering them helps an assistant accountant make sound business decisions.

1.1 Linear Equations

A linear equation is an equation in which the unknown is raised only to the power of one, such as 5x + 200 = 1,200, and its graph is a straight line.

Many business problems, such as finding how many units must be sold to break even, can be written and solved as linear equations.

Solving Simple Linear Equations

To solve a linear equation, do the same operation to both sides until the unknown stands alone: first remove added or subtracted numbers, then divide or multiply to remove the number in front of the unknown. Always check the answer by putting it back into the original equation.

Here you are finding the value of the unknown letter that makes both sides equal. Whatever you do to one side, do the same to the other: first clear brackets, then move all the letter terms to one side and the numbers to the other, and finally divide by the number in front of the letter. Check by putting your answer back into the equation. Below, we show you how it is done, step by step.

Solve 5x + 200 = 1,200.
  1. Subtract 200 from both sides: 5x = 1,200 − 200 = 1,000
  2. Divide both sides by 5: x = 1,000 ÷ 5 = 200
  3. Check: 5 × 200 + 200 = 1,200 ✓

Answer: x = 200

Solve 3(x − 4) = 2x + 6.
  1. Expand the bracket: 3x − 12 = 2x + 6
  2. Subtract 2x from both sides: x − 12 = 6
  3. Add 12 to both sides: x = 18

Answer: x = 18

Solve 7x − 9 = 3x + 15.
  1. Subtract 3x from both sides: 4x − 9 = 15
  2. Add 9 to both sides: 4x = 24
  3. Divide both sides by 4: x = 6
  4. Check: 7 × 6 − 9 = 33 and 3 × 6 + 15 = 33 ✓

Answer: x = 6

Solving Business Problems with Linear Equations

The process is to read the problem carefully, let a letter stand for the unknown, write an equation from the facts given, solve it, and answer the question in words, with the correct units.

Here you are turning a business story into an equation. Choose a letter for the amount you do not know, then write each fact in the story using that letter, and join them with an equals sign. Solve the equation, and finish by answering the question in words. Below, we show you how it is done, step by step.

A trader has fixed costs of $1,500 a month. Each item costs $12 to buy and sells for $18. How many items must be sold to break even?
  1. Let x be the number of items sold.
  2. Revenue = 18x; total cost = 1,500 + 12x
  3. Break even when revenue = total cost: 18x = 1,500 + 12x
  4. 18x − 12x = 1,500, so 6x = 1,500
  5. x = 1,500 ÷ 6 = 250

Answer: 250 items must be sold to break even

Wages for a casual worker are $30 a week plus $4 for every crate packed. One week she earned $110. How many crates did she pack?
  1. Let c be the number of crates: 30 + 4c = 110
  2. 4c = 110 − 30 = 80
  3. c = 80 ÷ 4 = 20

Answer: 20 crates

Three partners share $9,000. Anesu gets twice Bongani's share, and Chido gets $1,000 more than Bongani. Find each share.
  1. Let Bongani's share be b. Then Anesu = 2b and Chido = b + 1,000
  2. Equation: 2b + b + (b + 1,000) = 9,000
  3. 4b + 1,000 = 9,000, so 4b = 8,000
  4. b = 2,000, so Anesu = 4,000 and Chido = 3,000

Answer: Anesu $4,000; Bongani $2,000; Chido $3,000

1.2 Ratios, Rates, Percentages, Mixtures and Proportions

Ratios and percentages compare quantities, while rates compare quantities measured in different units.

Proportions show how one quantity changes when another changes, and mixtures combine items at different prices.

Rates

A rate compares two quantities measured in different units, such as $ per hour, km per litre or units per day. Rates are used to calculate wages, fuel costs and productivity, by multiplying the rate by the quantity.

Here you are using a rate, an amount per one unit of something else, to find a total. Write the rate clearly with its units, such as $ per hour or litres per 100 km. Multiply the rate by the quantity to find a total, or divide the total by the rate to find the quantity. Below, we show you how it is done, step by step.

A clerk is paid $3.50 an hour for a 40-hour week, and overtime at time-and-a-half. Find her pay for a week with 6 hours of overtime.
  1. Basic pay = 40 × $3.50 = $140
  2. Overtime rate = 1.5 × $3.50 = $5.25 an hour
  3. Overtime pay = 6 × $5.25 = $31.50
  4. Total = 140 + 31.50 = $171.50

Answer: $171.50

A delivery truck uses 12 litres of fuel per 100 km. Fuel costs $1.60 a litre. Find the fuel cost of a 450 km trip.
  1. Litres needed = 450 ÷ 100 × 12 = 54 litres
  2. Cost = 54 × 1.60 = $86.40

Answer: $86.40

A machine fills 240 bottles an hour. How long will it take to fill 3,000 bottles?
  1. Time = total ÷ rate = 3,000 ÷ 240 = 12.5 hours
  2. 0.5 hours = 30 minutes

Answer: 12 hours 30 minutes

Comparing Quantities Using Ratios

A ratio compares two or more quantities of the same kind, written as a:b, and is simplified by dividing all parts by the same number, so 40:60 becomes 2:3. To share an amount in a given ratio, add the parts, find the value of one part, and multiply.

Here you are sharing an amount in a ratio or simplifying a ratio. To share, add the parts of the ratio, divide the amount by the total parts to get one part, then multiply by each person's number of parts. To simplify, divide every part by the largest number that goes into all of them. Below, we show you how it is done, step by step.

Partners Tendai and Rufaro share a profit of $18,000 in the ratio 3:2. Find each share.
  1. Total parts = 3 + 2 = 5
  2. One part = 18,000 ÷ 5 = $3,600
  3. Tendai = 3 × 3,600 = $10,800
  4. Rufaro = 2 × 3,600 = $7,200

Answer: Tendai $10,800 and Rufaro $7,200

Simplify 450 : 300 : 150, then share $12,000 in that ratio.
  1. Divide each part by 150: 450 : 300 : 150 = 3 : 2 : 1
  2. Total parts = 3 + 2 + 1 = 6; one part = 12,000 ÷ 6 = $2,000
  3. Shares: 3 × 2,000 = $6,000; 2 × 2,000 = $4,000; 1 × 2,000 = $2,000

Answer: $6,000, $4,000 and $2,000

Profit is shared between Tendai and Rufaro in the ratio 5 : 3. Rufaro receives $4,500. Find Tendai's share and the total profit.
  1. Rufaro's 3 parts = $4,500, so one part = 4,500 ÷ 3 = $1,500
  2. Tendai = 5 × 1,500 = $7,500
  3. Total = 8 × 1,500 = $12,000

Answer: Tendai $7,500; total profit $12,000

Fractions, Decimals and Percentages

A percentage is a fraction out of 100. To change a fraction or decimal to a percentage, multiply by 100: ¾ = 0.75 = 75%. To find a percentage of an amount, multiply the amount by the percentage over 100. Percentage change = change ÷ original × 100, and to increase an amount by r%, multiply by (1 + r/100).

Here you are working with percentages of amounts and percentage changes. To find a percentage of an amount, multiply by the percentage over 100. For a percentage change, divide the change by the original figure and multiply by 100; to undo an increase, divide the new figure by (1 + the rate). Below, we show you how it is done, step by step.

Sales rose from $40,000 to $46,000. Find the percentage increase.
  1. Increase = 46,000 − 40,000 = $6,000
  2. Percentage increase = 6,000 ÷ 40,000 × 100 = 15%

Answer: 15% increase

Goods cost $80. They are sold at a mark-up of 25%. Find the selling price and the margin.
  1. Profit = 25% × 80 = $20
  2. Selling price = 80 + 20 = $100
  3. Margin = profit ÷ selling price × 100 = 20 ÷ 100 × 100 = 20%

Answer: Selling price $100; margin 20%

After a 15% price increase, an item costs $230. What was the price before the increase?
  1. The new price is 115% of the old price
  2. Old price = 230 ÷ 1.15 = $200
  3. Check: 200 + 15% × 200 = 200 + 30 = $230 ✓

Answer: $200

Mixtures

A mixture problem combines items with different prices, such as blends of tea or mixed fruit packs, and asks for the price of the mixture or the quantities to mix. The price of a mixture is its total cost divided by its total quantity.

Here you are working out the price of a mixture, or how much of each item to mix. Find the total cost of everything mixed and divide by the total quantity to get the cost per unit. When the quantities are unknown, let one quantity be x and write an equation for the total cost. Below, we show you how it is done, step by step.

A shop mixes 30 kg of rice at $1.20 per kg with 20 kg at $1.70 per kg. Find the cost per kg of the mixture.
  1. Cost of first rice = 30 × 1.20 = $36
  2. Cost of second rice = 20 × 1.70 = $34
  3. Total cost = 36 + 34 = $70 for 30 + 20 = 50 kg
  4. Cost per kg = 70 ÷ 50 = $1.40

Answer: $1.40 per kg

Tea at $4 per kg is mixed with tea at $7 per kg to make 30 kg costing $5 per kg. How much of each is used?
  1. Let x kg be the $4 tea; then the $7 tea is (30 − x) kg
  2. Total cost: 4x + 7(30 − x) = 30 × 5 = 150
  3. 4x + 210 − 7x = 150, so −3x = −60
  4. x = 20 kg of $4 tea; 30 − 20 = 10 kg of $7 tea

Answer: 20 kg at $4 and 10 kg at $7

40 kg of beans at $1.20 per kg are mixed with 20 kg at $1.50 per kg, and the mixture is sold at a 25% mark-up. Find the selling price per kg.
  1. Total cost = (40 × 1.20) + (20 × 1.50) = 48 + 30 = $78
  2. Cost per kg = 78 ÷ 60 = $1.30
  3. Selling price = 1.30 × 1.25 = $1.625, about $1.63 per kg

Answer: About $1.63 per kg

Direct and Inverse Proportion

In direct proportion, two quantities increase or decrease together at the same rate, so doubling one doubles the other; for example, the cost of goods rises with the quantity bought. In inverse proportion, one quantity increases as the other decreases, so doubling one halves the other; for example, the more workers on a job, the fewer days it takes.

Here you are deciding whether two quantities move together or in opposite directions. In direct proportion, find the value for one unit and multiply; in inverse proportion, multiply the two given figures to get the total work, then divide by the new figure. Always ask: should my answer be bigger or smaller? Below, we show you how it is done, step by step.

Direct: 12 reams of paper cost $72. Find the cost of 20 reams.
  1. Cost of 1 ream = 72 ÷ 12 = $6
  2. Cost of 20 reams = 20 × 6 = $120

Answer: $120

Inverse: 6 workers take 10 days to complete a stocktake. How long would 4 workers take?
  1. Total work = 6 × 10 = 60 worker-days
  2. Days for 4 workers = 60 ÷ 4 = 15

Answer: 15 days

Animal feed lasts 40 cattle for 30 days. How long would it last 60 cattle?
  1. More cattle means fewer days, so this is inverse proportion
  2. Total feed = 40 × 30 = 1,200 cattle-days
  3. Days for 60 cattle = 1,200 ÷ 60 = 20 days

Answer: 20 days

1.3 Discounts and Commissions

A discount is a reduction in price, while a commission is a payment based on the value of sales or business done.

Both are usually calculated as percentages.

Types of Discounts

A trade discount is a reduction given by a manufacturer or wholesaler to other traders, off the list price, and is not recorded in the ledger. A cash discount (discount allowed or received) is given for paying promptly, such as 5% if paid within 14 days, and is recorded in the books. A quantity (bulk) discount is given for buying large quantities, and a seasonal discount for buying out of season. When there is both a trade and a cash discount, the trade discount is deducted first.

Here you are finding what a customer pays after discounts. Always take off the trade discount first, from the list price, to get the invoice amount. Then take the cash discount off the invoice amount, but only if the customer pays within the time allowed. Below, we show you how it is done, step by step.

Goods listed at $2,000 are sold with 20% trade discount and 5% cash discount for payment within 14 days. Find the amount paid if the buyer pays on time.
  1. Trade discount = 20% × 2,000 = $400
  2. Invoice amount = 2,000 − 400 = $1,600
  3. Cash discount = 5% × 1,600 = $80
  4. Amount paid = 1,600 − 80 = $1,520

Answer: $1,520

Goods with a list price of $800 are sold at 25% trade discount, with 2.5% cash discount for payment within 7 days. Find the amount paid if the customer pays on time, and if the customer pays late.
  1. Trade discount = 25% × 800 = $200; invoice = 800 − 200 = $600
  2. On time: cash discount = 2.5% × 600 = $15, so pay 600 − 15 = $585
  3. Late: no cash discount, so pay $600

Answer: $585 on time; $600 if late

A wholesaler sells at $12 a unit and gives a 10% quantity discount on orders of 100 units or more. Find the cost of 150 units.
  1. Full price = 150 × 12 = $1,800
  2. Quantity discount = 10% × 1,800 = $180
  3. Amount payable = 1,800 − 180 = $1,620

Answer: $1,620, which is $10.80 a unit

Types of Commission

A sales commission is paid to salespeople as a percentage of the sales they make, sometimes on top of a basic salary. An agent's commission is paid to an agent, such as an estate agent or insurance agent, for arranging a sale. A graduated (sliding scale) commission pays a higher rate on sales above a target. Del credere commission is an extra commission paid to an agent who guarantees that customers will pay.

Here you are working out commission as a percentage of sales. Multiply the sales by the commission rate; on a sliding scale, split the sales into bands and use each band's rate. To find the sales from the commission, divide the commission by the rate. Below, we show you how it is done, step by step.

A salesperson earns a basic $200 a month plus 3% commission on the first $10,000 of sales and 5% on sales above $10,000. Sales for the month were $16,000. Find her total earnings.
  1. Commission on first $10,000 = 3% × 10,000 = $300
  2. Sales above $10,000 = 16,000 − 10,000 = $6,000
  3. Commission on the rest = 5% × 6,000 = $300
  4. Total = 200 + 300 + 300 = $800

Answer: $800

An estate agent sells a house for $60,000 and earns 2.5% commission. Find the commission.
  1. Commission = 2.5% × 60,000
  2. Commission = 0.025 × 60,000 = $1,500

Answer: $1,500

A salesperson earned $650 commission at 5% of sales. What were the sales?
  1. Commission = 5% of sales, so sales = 650 ÷ 0.05
  2. Sales = $13,000

Answer: $13,000

1.4 Hire Purchase

Hire purchase allows a buyer to take goods now and pay for them in instalments over time.

It makes expensive items affordable, but the total paid is higher than the cash price.

Meaning of Hire Purchase

Hire purchase (HP) is an agreement in which the buyer pays a deposit and then a number of instalments, and uses the goods from the start, but ownership passes to the buyer only when the last instalment is paid. If the buyer fails to pay, the seller may repossess the goods, subject to the law and the terms of the agreement.

Hire Purchase Price and Cash Price

The cash price is the price paid if the goods are bought outright today. The hire purchase price is the total of the deposit and all the instalments. The difference between them is the HP charge, or interest, which is the cost of paying over time. Buyers should compare the two and work out the interest rate before signing.

Solving Hire Purchase Problems

The procedure is: find the deposit, find the total of the instalments (number × amount), add them to get the HP price, then subtract the cash price to get the HP charge, and express it as a percentage of the cash price if asked.

Here you are comparing the hire purchase price with the cash price. Work out the deposit, then the total of all the instalments, and add them to get the HP price. The extra cost is the HP price minus the cash price, and you can show it as a percentage of the cash price. Below, we show you how it is done, step by step.

A refrigerator has a cash price of $900. On hire purchase it requires a 20% deposit and 12 monthly instalments of $70. Find the HP price, the extra cost, and the extra cost as a percentage of the cash price.
  1. Deposit = 20% × 900 = $180
  2. Instalments = 12 × 70 = $840
  3. HP price = 180 + 840 = $1,020
  4. Extra cost = 1,020 − 900 = $120
  5. As a percentage = 120 ÷ 900 × 100 = 13.3%

Answer: HP price $1,020; extra cost $120, which is 13.3% of the cash price

A TV has a cash price of $500. On HP, the deposit is $50 and there are 10 monthly instalments of $55. Find the HP price and the extra cost as a percentage.
  1. Instalments = 10 × 55 = $550
  2. HP price = 50 + 550 = $600
  3. Extra cost = 600 − 500 = $100
  4. As a percentage = 100 ÷ 500 × 100 = 20%

Answer: HP price $600; extra cost $100 (20%)

A sofa costs $1,200 cash. On HP, a 25% deposit is paid and the balance, plus simple interest at 10% a year for 2 years, is paid in 24 equal monthly instalments. Find the instalment and the HP price.
  1. Deposit = 25% × 1,200 = $300; balance = $900
  2. Interest = 900 × 0.10 × 2 = $180
  3. Amount to repay = 900 + 180 = $1,080; instalment = 1,080 ÷ 24 = $45
  4. HP price = 300 + 1,080 = $1,380

Answer: Instalment $45; HP price $1,380

1.5 Currency Conversion

Businesses in Zimbabwe often deal in more than one currency, such as the US dollar, the ZiG and the South African rand.

Converting correctly between them is essential for pricing, paying suppliers and recording transactions.

Meaning of Currency

A currency is the money accepted as a medium of exchange in a country, such as the US dollar (USD), the Zimbabwe Gold (ZiG), the South African rand (ZAR) and the pound sterling (GBP).

An exchange rate is the price of one currency in terms of another, for example US$1 = R18.50, so it tells us how many units of one currency are needed to buy one unit of another.

Different Currency Rates

A bank's buying rate is the rate at which the bank buys foreign currency from customers, and its selling rate is the rate at which it sells foreign currency to customers; the selling rate is less favourable to the customer, and the difference is the bank's profit. The official or interbank rate is set or published by the central bank, while a cross rate is an exchange rate between two currencies worked out through a third currency. Rates change often, so the rate for the actual date must always be used. The rates in the examples are for illustration only.

Currency Conversion Methods

When the rate is given as 1 unit of A = r units of B, multiply to change A into B and divide to change B into A. A cross rate is found by combining two rates through a common currency.

Here you are changing money from one currency to another. Write the rate as 1 unit of one currency = so many units of the other, then multiply to go from the first currency to the second and divide to go back. When buying and selling rates are given, remember the bank always uses the rate that is better for the bank. Below, we show you how it is done, step by step.

Using US$1 = R18.50, convert US$400 to rand, and R9,250 to US dollars.
  1. US$ to rand: multiply, 400 × 18.50 = R7,400
  2. Rand to US$: divide, 9,250 ÷ 18.50 = US$500

Answer: R7,400 and US$500

If US$1 = R18.50 and £1 = US$1.25, find the cross rate of rand per pound.
  1. £1 = US$1.25
  2. US$1.25 = 1.25 × 18.50 rand = R23.125
  3. So £1 = R23.13 (to 2 decimal places)

Answer: £1 = R23.13

A bank's rates are: buys US$1 for R18.20 and sells US$1 for R18.80. A trader changes R9,400 into US dollars, then later changes the dollars back to rand. Find the loss.
  1. Rand to dollars: the bank sells dollars at R18.80, so 9,400 ÷ 18.80 = US$500
  2. Dollars to rand: the bank buys dollars at R18.20, so 500 × 18.20 = R9,100
  3. Loss = 9,400 − 9,100 = R300

Answer: A loss of R300 from the difference between the rates

All Financial Mathematics and Statistics 1 learning outcomes

  1. Learning Outcome 1: Business Computations
  2. Learning Outcome 2: Financial Statistics
  3. Learning Outcome 3: Time Value of Money